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Ethylamine reacts with nitrous acid at low temperature to form:
- (a)$\text{C}_2\text{H}_5\text{N}_2\text{Cl}, \text{H}_2\text{O}$
- (b)$\text{C}_2\text{H}_5\text{OH}, \text{C}_2\text{H}_5\text{NO}_2$
- (c)$\text{C}_2\text{H}_5\text{OH}, \text{N}_2, \text{H}_2\text{O}$
- (d)$\text{C}_2\text{H}_5\text{OH}, \text{NH}_3, \text{H}_2\text{O}$
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From ISC 2025 Improvement Chemistry Paper 1, question 1(B)(i).