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Answer the following.
The molar mass calculated through colligative properties is sometimes different from that of…
The molar mass calculated through colligative properties is sometimes different from that of experimentally determined molecular mass and is known as abnormal molecular mass. This difference is due to the solute particles that undergo association or dissociation. Consider the two cases given below and answer the questions that follow.
(A) The freezing point of a solution containing $5.85\text{ g}$ of $\text{NaCl}$ in $100\text{ g}$ of water is $-3.348^\circ\text{C}$. ($K_f$ of water $= 1.86\text{ K kg mol}^{-1}$, molecular mass of $\text{NaCl} = 58.5$)
(B) The freezing point of benzene solution decreases by $0.45^\circ\text{C}$ when $0.2\text{ g}$ of acetic acid is added to $20\text{ g}$ of benzene. ($K_f$ of benzene $= 5.12\text{ K kg mol}^{-1}$, molecular mass of acetic acid $= 60$)
Inferring the value of van't Hoff factor in both the cases, find out which solution undergoes association and which solution undergoes dissociation.
Answer
Answer
Official answer key[A] undergoes Dissociation while [B] undergoes Association
From ISC 2025 Specimen Chemistry Paper 1, question 13(ii).
Check your working with the Molar mass calculator: molar mass of any formula, hydrates too, with the working and percentage composition.
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