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Answer the following.

The molar mass calculated through colligative properties is sometimes different from that of…

Chemistry20251 markShort answer
The molar mass calculated through colligative properties is sometimes different from that of experimentally determined molecular mass and is known as abnormal molecular mass. This difference is due to the solute particles that undergo association or dissociation. Consider the two cases given below and answer the questions that follow. (A) The freezing point of a solution containing $5.85\text{ g}$ of $\text{NaCl}$ in $100\text{ g}$ of water is $-3.348^\circ\text{C}$. ($K_f$ of water $= 1.86\text{ K kg mol}^{-1}$, molecular mass of $\text{NaCl} = 58.5$) (B) The freezing point of benzene solution decreases by $0.45^\circ\text{C}$ when $0.2\text{ g}$ of acetic acid is added to $20\text{ g}$ of benzene. ($K_f$ of benzene $= 5.12\text{ K kg mol}^{-1}$, molecular mass of acetic acid $= 60$) Given below is the increasing order of depression in freezing point of water observed for equimolar concentrations of the compounds, acetic acid < trichloro acetic acid < trifluoro acetic acid Provide a reason to explain if the above ordered arrangement is correct or not.

Answer

Answer

Official answer key
The given order of depression in freezing point is correct, as $\Delta T_f$ depends on the number of moles of solute.
Solutions

From ISC 2025 Specimen Chemistry Paper 1, question 13(iii).

Check your working with the Molar mass calculator: molar mass of any formula, hydrates too, with the working and percentage composition.

Check your working with the Chemistry numericals calculator: solutions, electrochemistry and kinetics formulas: fill in what you know and get the rest.