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Answer the following.
An organic compound [X] with molecular formula forms compound [Y] on oxidation. Compound [X]…
An organic compound [X] with molecular formula $\text{C}_2\text{H}_4\text{O}$ forms compound [Y] on oxidation. Compound [X] undergoes haloform reaction. On treatment with $\text{HCN}$, compound [X] forms a product [Z] which on hydrolysis gives 2-hydroxy propanoic acid.
(a) Write down the structures of compounds [X] and [Y].
(b) Name the product formed when [X] reacts with dil. $\text{NaOH}$.
Answer
Answer
AI(a) Structures of compounds [X] and [Y]:
Compound [X]: Acetaldehyde (ethanal), $\text{CH}_3-\text{CHO}$
Compound [Y]: Acetic acid (ethanoic acid), $\text{CH}_3-\text{COOH}$
(b) When acetaldehyde [X] reacts with dilute $\text{NaOH}$, it undergoes aldol condensation to form 3-hydroxybutanal (aldol).
From ISC 2026 Chemistry Paper 1, question 20(ii).
Check your working with the IUPAC name to structure: draw the structure of an organic compound from its IUPAC name, with formula and functional groups.