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Answer the following.

concentration of only [B] is increased three times?

Chemistry20261 markShort answer

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The rate law is $\text{Rate} = k[\text{A}][\text{B}]^2$. When $[\text{B}]$ is increased three times: $\text{Rate}' = k[\text{A}](3[\text{B}])^2 = 9 k[\text{A}][\text{B}]^2 = 9 \times \text{Rate}$ The rate of reaction increases by 9 times (becomes 9 times the initial rate).
Chemical Kinetics

From ISC 2026 Chemistry Paper 1, question 2(i).