Identify the compounds A, B, C and D.
$\text{C}_6\text{H}_5\text{COOH} \xrightarrow{\text{SOCl}_2} \text{A} \xrightarrow{\text{NH}_3} \text{B} \xrightarrow{\text{Br}_2 / \text{KOH}} \text{C} \xrightarrow[0 - 5^\circ\text{C}]{\text{NaNO}_2 + \text{HCl}} \text{D}$
Answer
Answer
AI
A - benzoyl chloride: C6H5COCl
B - benzamide: C6H5CONH2
C - aniline: C6H5NH2
D - benzenediazonium chloride: C6H5N2Cl
A = benzoyl chloride ($\mathrm{C_6H_5COCl}$)
B = benzamide ($\mathrm{C_6H_5CONH_2}$)
C = aniline ($\mathrm{C_6H_5NH_2}$), by Hofmann bromamide degradation
D = benzenediazonium chloride ($\mathrm{C_6H_5N_2^+Cl^-}$)