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If , and is a unit vector then the angle between and will be:
If $|\vec{a}| = 3$, $|\vec{b}| = \frac{\sqrt{2}}{3}$ and $\vec{a} \times \vec{b}$ is a unit vector then the angle between $\vec{a}$ and $\vec{b}$ will be:
- (a)$\frac{\pi}{6}$
- (b)$\frac{\pi}{4}$
- (c)$\frac{\pi}{3}$
- (d)$\frac{\pi}{2}$
Answer
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From ISC 2023 Mathematics Paper 1, question 15(i).