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Show that:

Mathematics20184 marksDerivation
Show that: $(\vec{a} \times \vec{b})^2 = \begin{vmatrix} \vec{a} \cdot \vec{a} & \vec{a} \cdot \vec{b} \\ \vec{a} \cdot \vec{b} & \vec{b} \cdot \vec{b} \end{vmatrix}$

Given: $(\vec{a} \times \vec{b})^2$

To show: $\begin{vmatrix} \vec{a} \cdot \vec{a} & \vec{a} \cdot \vec{b} \\ \vec{a} \cdot \vec{b} & \vec{b} \cdot \vec{b} \end{vmatrix}$

Answer

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Vectors

From ISC 2018 Specimen Mathematics Paper 1, question 16(a).