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Show that:
Show that:
$\vec{a} \cdot (\vec{b} + \vec{c}) \times (\vec{a} + 2\vec{b} + 3\vec{c}) = [\vec{a} \; \vec{b} \; \vec{c}]$
Given: $\vec{a} \cdot (\vec{b} + \vec{c}) \times (\vec{a} + 2\vec{b} + 3\vec{c})$
To show: $[\vec{a} \; \vec{b} \; \vec{c}]$
Answer
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From ISC 2018 Specimen Mathematics Paper 1, question 16(b).