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In the reaction , the rate law is . How will the rate of reaction change if concentration is…
In the reaction $2\text{NO} + \text{O}_2 \longrightarrow 2\text{NO}_2$, the rate law is $\text{rate} = k[\text{NO}][\text{O}_2]^2$.
(i)[1.0]
How will the rate of reaction change if $[\text{NO}]$ concentration is doubled and $[\text{O}_2]$ concentration is halved at the same time?
(ii)[1.0]
Write the order of reaction if $[\text{NO}]$ concentration is in large excess.
Answer
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From ISC 2025 Chemistry Paper 1, question 4.