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A parallel plate capacitor is charged by a battery; which is then disconnected. A dielectric slab…

Physics20183 marksShort answer
A parallel plate capacitor is charged by a battery; which is then disconnected. A dielectric slab is now introduced between the two plates to occupy the space completely. State the effect on the following:
(i)
the capacitance of the capacitor.
(ii)
potential difference between the plates.
(iii)
the energy stored in the capacitor.

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Electrostatic Potential, Potential Energy and Capacitance

From ISC 2018 Specimen Physics Paper 1, question 14(b).