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If then the number of point(s) of discontinuity of , is / are:
If $f(x) = \begin{cases} x+2 & x < 0 \\ -x^2-2 & 0 \le x < 1 \\ x & x \ge 1 \end{cases}$ then the number of point(s) of discontinuity of $f(x)$, is / are:
- (a)$1$
- (b)$3$
- (c)$2$
- (d)$0$
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From ISC 2025 Mathematics Paper 1, question 1(viii).