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If , prove that
If $x^y = e^{x-y}$, prove that $\frac{dy}{dx} = \frac{\log x}{(1+\log x)^2}$
Given: $x^y = e^{x-y}$
To show: \frac{dy}{dx} = \frac{\log x}{(1+\log x)^2}
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From ISC 2025 Mathematics Paper 1, question 4(i).