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Solve the following.
Prove: .
Prove: $2\sin^{-1}x = \sin^{-1}(2x\sqrt{1 - x^2})$.
Given: $x = \sin\theta$
To show: $2\sin^{-1}x = \sin^{-1}(2x\sqrt{1 - x^2})$
Answer
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From ISC 2025 Improvement Mathematics Paper 1, question 14(ii).