‹ Back to the paper
is equal to:
$\int_0^1 \frac{x^4 - 1}{x^2 + 1}\,dx$ is equal to:
- (a)$\frac{2}{3}$
- (b)$\frac{1}{3}$
- (c)$-\frac{2}{3}$
- (d)$0$
Answer
No answer yet.
From ISC 2025 Mathematics Paper 1, question 1(iv).