‹ Back to the paper
If , prove that
If $x = \sin t, y = \sin pt$, prove that $(1 - x^2)\frac{d^2y}{dx^2} - x\frac{dy}{dx} + p^2 y = 0$
Given: $x = \sin t, y = \sin pt$
To show: (1 - x^2)\frac{d^2y}{dx^2} - x\frac{dy}{dx} + p^2 y = 0
Answer
No answer yet.
From ISC 2025 Improvement Mathematics Paper 1, question 8(i).