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If , then ( ) is equal to
If $A = \begin{pmatrix} 1 & b \\\\ 0 & 1 \end{pmatrix}$, then $A^n$ ($n \in \mathbb{N}$) is equal to
- (a)$\begin{pmatrix} 1 & nb \\\\ 0 & 1 \end{pmatrix}$
- (b)$\begin{pmatrix} 1 & b^n \\\\ 0 & 1 \end{pmatrix}$
- (c)$\begin{pmatrix} 1 & nb \\\\ 0 & 1 \end{pmatrix}$
- (d)$\begin{pmatrix} 1 & nb \\\\ 0 & 0 \end{pmatrix}$
Answer
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From ISC 2023 Specimen Mathematics Paper 1, question 1(iv).