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Show that and intersect each other. Also find out the point of intersection.
Show that $\frac{4-x}{-1} = \frac{y+3}{-4} = \frac{z+1}{7}$ and $\frac{x-1}{2} = \frac{y+1}{-3} = \frac{z+10}{8}$ intersect each other. Also find out the point of intersection.
Given: Line 1: $\frac{4-x}{-1} = \frac{y+3}{-4} = \frac{z+1}{7}$, Line 2: $\frac{x-1}{2} = \frac{y+1}{-3} = \frac{z+10}{8}$
To show: They intersect each other and find their point of intersection.
Answer
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From ISC 2023 Specimen Mathematics Paper 1, question 17(i).