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If , then the value of is equal to
If $\begin{vmatrix} a & b & c \\\\ x+a & y+2a & z+3a \\\\ 1 & 2 & 3 \end{vmatrix} = \begin{vmatrix} a & b & c \\\\ x & y & z \\\\ 1 & 2 & 3 \end{vmatrix} + |B|$, then the value of $|B|$ is equal to
- (a)$a + 2b + 3c$
- (b)$a - b + 2c$
- (c)$0$
- (d)$3a$
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From ISC 2023 Specimen Mathematics Paper 1, question 1(vi).