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Answer the following.
An aqueous solution contains of protein in of water. The osmotic pressure of the solution at is …
An aqueous solution contains $0\cdot63\text{ g}$ of protein in $300\text{ cm}^3$ of water. The osmotic pressure of the solution at $300\text{ K}$ is $1\cdot29 \times 10^{-3}\text{ atm}$. Calculate the molecular mass of protein.
(Given $R = 0\cdot0821\text{ Lit atm K}^{-1}\text{ mol}^{-1}$)
Answer
Answer
Official answer key$\pi V = \dfrac{w}{M}RT$, so $M = \dfrac{wRT}{\pi V} = \dfrac{0.63\times0.0821\times300}{1.29\times10^{-3}\times0.3} = 40095\ \mathrm{g\,mol^{-1}}$
Final answer: 40095 g mol^-1
From ISC 2026 Specimen Chemistry Paper 1, question 20(i).
Check your working with the Molar mass calculator: molar mass of any formula, hydrates too, with the working and percentage composition.
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