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Water vapour and liquid water are in equilibrium in a container. At room temperature, the vapour…
Water vapour and liquid water are in equilibrium in a container. At room temperature, the vapour pressure of water is $25\text{ mm of Hg}$. The volume of water is $V\text{ ml}$.
(i)[1.5]
What will be the vapour pressure of water if the volume of water is reduced to $V/4\text{ ml}$ without any change in temperature? Give a reason.
(ii)[1.5]
Will there be a change in vapour pressure if more water (at room temperature) is added to the container? Give a reason.
Answer
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From ISC 2024 Specimen Chemistry Paper 1, question 15.