A monochromatic ray of light incident on one refracting surface of an equilateral prism, suffers a…
A monochromatic ray of light incident on one refracting surface of an equilateral prism, suffers a deviation as shown in the Figure 7 below:

(i)[2.0]
Calculate the refractive index of the material of the prism.
(ii)[1.0]
What is meant by dispersive power of a transparent material?
Answer
Answer (i)
AIWritten by AI - it can contain mistakes.
From Figure 7, the refracted ray inside the equilateral prism is parallel to the base, which means the prism is in the minimum deviation position ($\delta_m = 40^\circ$).
For an equilateral prism, angle of prism $A = 60^\circ$.
Using the prism formula:
$\mu = \frac{\sin\left(\frac{A + \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}$
$\mu = \frac{\sin\left(\frac{60^\circ + 40^\circ}{2}\right)}{\sin\left(\frac{60^\circ}{2}\right)} = \frac{\sin 50^\circ}{\sin 30^\circ} = \frac{0\cdot766}{0\cdot5} = 1\cdot532 \approx 1\cdot53$
Final answer: 1.53
Final answer: 1.53
Answer (ii)
AIWritten by AI - it can contain mistakes.
Dispersive power ($\omega$) of a transparent material is defined as the ratio of angular dispersion between two extreme colours (violet and red) to the mean deviation produced by a thin prism of that material:
$\omega = \frac{\delta_V - \delta_R}{\delta_Y} = \frac{\mu_V - \mu_R}{\mu_Y - 1}$
From ISC 2026 Physics Paper 1, question 13.