Answer the following: Compounds [X] and [Y] are functional isomers of each other with molecular…
Answer the following:
(i)
Compounds [X] and [Y] are functional isomers of each other with molecular formula $\text{C}_2\text{H}_6\text{O}$.
(a) Draw the structural formula of both the isomers.
(b) Which of the compounds will have a lower boiling point and why?
(ii)
Methanol does not give yellow precipitate of iodoform when heated with iodine and alkali, but ethanol gives iodoform test with the same reagents. Explain.
Answer
Answer (i)
AIWritten by AI (gemini) - it can contain mistakes.
(a) Functional isomers of $\text{C}_2\text{H}_6\text{O}$:
Ethanol: $\text{CH}_3\text{CH}_2\text{OH}$
Dimethyl ether: $\text{CH}_3-\text{O}-\text{CH}_3$
(b) Dimethyl ether has a lower boiling point because it lacks intermolecular hydrogen bonding, whereas ethanol molecules are strongly associated through intermolecular hydrogen bonding.
Answer (ii)
AIWritten by AI (gemini) - it can contain mistakes.
Ethanol contains the $\text{CH}_3-\text{CH(OH)}-$ grouping, which upon oxidation with hypoiodite gives $\text{CH}_3\text{CHO}$ containing the $\text{CH}_3\text{CO}-$ group, thus forming yellow precipitate of iodoform ($\text{CHI}_3$). Methanol ($\text{CH}_3\text{OH}$) does not have the $\text{CH}_3\text{CH(OH)}-$ group and cannot give the iodoform test.
From ISC 2027 Specimen Chemistry Paper 1, question 14(i).