The standard reduction electrode potential ( ) of some metals is given below: | Metal | | | :--- |…
The standard reduction electrode potential ($E^\circ$) of some metals is given below:
Arrange these metals in the increasing order of their reducing power. Justify the order.
| Metal | $E^\circ$ |
|---|---|
| $\text{Ag}^+/\text{Ag}$ | $+0\cdot80\text{ V}$ |
| $\text{Mg}^{2+}/\text{Mg}$ | $-2\cdot37\text{ V}$ |
| $\text{Li}^+/\text{Li}$ | $-3\cdot05\text{ V}$ |
| $\text{Cu}^{2+}/\text{Cu}$ | $+0\cdot34\text{ V}$ |
| $\text{Fe}^{2+}/\text{Fe}$ | $-0\cdot44\text{ V}$ |
Answer
Answer
AIWritten by AI (gemini) - it can contain mistakes.
Increasing order of reducing power of metals: $\text{Ag} < \text{Cu} < \text{Fe} < \text{Mg} < \text{Li}$.
Justification: Reducing power is inversely proportional to reduction potential ($\text{Reducing power} \propto \frac{1}{\text{Reduction potential}}$). As the standard reduction potential decreases (becomes more negative), the tendency to lose electrons increases, hence the reducing power of the metal increases.
From ISC 2027 Specimen Chemistry Paper 1, question 2.