The correct order of freezing point of solution of urea, , and is:
The correct order of freezing point of $0\cdot5\text{ M}$ solution of urea, $\text{AlCl}_3$, $\text{KCl}$ and $\text{MgCl}_2$ is:
- a$\text{AlCl}_3 > \text{MgCl}_2 > \text{KCl} > \text{urea}$
- b$\text{Urea} > \text{KCl} > \text{MgCl}_2 > \text{AlCl}_3$
- c$\text{MgCl}_2 > \text{KCl} > \text{AlCl}_3 > \text{urea}$
- d$\text{KCl} > \text{MgCl}_2 > \text{AlCl}_3 > \text{urea}$
Answer
Answer
AIWritten by AI (gemini) - it can contain mistakes.
Correct option: b
Answer: (b) Urea > KCl > MgCl2 > AlCl3
Depression in freezing point is a colligative property proportional to the van 't Hoff factor $i$. Higher $i$ results in lower freezing point. For urea $i = 1$, for $\text{KCl}$ $i = 2$, for $\text{MgCl}_2$ $i = 3$, and for $\text{AlCl}_3$ $i = 4$.
From ISC 2027 Specimen Chemistry Paper 1, question 1(B)(i).